CUET UG Categorized PYQ Biology Unit 1
BIOLOGY
๐ Answers are locked once submitted โ results and explanations appear at the end.
QUESTION 1 OF 27
Types of cells in 2 celled pollen grains are ______. (PYQ 2022 Shift 1)
QUESTION 2 OF 27
What will be the number of chromosomes in the gamete of maize if its meiocyte contains 20 chromosomes? (PYQ 2023 Shift 1)
QUESTION 3 OF 27
Which layer of microsporangium nourishes the developing pollen grains? (PYQ 2023 Shift 1)
QUESTION 4 OF 27
Match the following: (PYQ 2023 Shift 1)
| List I | List II |
|---|---|
| A. Albuminous seed | I. Groundnut |
| B. Parthenocarpic fruit | II. Apple |
| C. Non-albuminous seed | III. Castor |
| D. False fruit | IV. Banana |
QUESTION 5 OF 27
Maximum number of male gametes produced from one pollen mother cell (microspore mother cell) will be : (PYQ 2023 Shift 2)
QUESTION 6 OF 27
QUESTION 7 OF 27
QUESTION 8 OF 27
QUESTION 9 OF 27
QUESTION 10 OF 27
QUESTION 11 OF 27
In artificial hybridisation bagging is done to: (PYQ 2023 Shift 3)
QUESTION 12 OF 27
Match List I with List II (PYQ 2023 Shift 3)
| List I | List II |
|---|---|
| A. Attaches ovule to the placenta | I. Hilum |
| B. Region where ovule fuses with its stalk | II. Chalaza |
| C. Place where integuments are not present | III. Funicle |
| D. Basal part of ovule | IV. Micropyle |
QUESTION 13 OF 27
The method of embryo sac formation from a single megaspore is termed ______ development. (PYQ 2023 Shift 3)
QUESTION 14 OF 27
Identify the correct statements with respect to female gametophyte. (PYQ 2023 Shift 3)
(A) Three cells at the chalazal end group together to form egg apparatus
(B) Female gametophyte is also known as embryo sac
(C) Six of the eight nuclei in the embryo sac are surrounded by cell walls and organised into cells
(D) Megaspore mother cell forms four megaspores by meiotic division
Choose the correct answer from the options given below:
QUESTION 15 OF 27
During megasporogenesis in a typical angiosperm ovule, which of the following correctly describes the formation and fate of megaspores? (PYQ 2023 Shift 3)
QUESTION 16 OF 27
Which part of the ovule differentiates a large cell with dense cytoplasm and a prominent nucleus during megasporogenesis? (PYQ 2023 Shift 3)
QUESTION 17 OF 27
How many mitotic divisions occur in the nucleus of the functional megaspore to form embryo sac? (PYQ 2023 Shift 3)
QUESTION 18 OF 27
In a velvet grass seed, the cotyledon is called : (PYQ 2024 Shift 1, 2024 Shift 2)
QUESTION 19 OF 27
Which one of the following is not associated with megasporangium ? (PYQ 2024 Shift 1)
QUESTION 20 OF 27
In diploid organisms, which of the following undergoes meiosis? (PYQ 2024 Shift 1)
QUESTION 21 OF 27
Which one of the following guides the entry of the pollen tube into the embryo sac? (PYQ 2025 Shift 1)
QUESTION 22 OF 27
Which one of the following is opposite part of micropylar end of ovule? (PYQ 2025 Shift 1)
QUESTION 23 OF 27
QUESTION 24 OF 27
QUESTION 25 OF 27
QUESTION 26 OF 27
QUESTION 27 OF 27
Test Complete!
Answer Review
1 Types of cells in 2 celled pollen grains are ______. (PYQ 2022 Shift 1)
Mature pollen grain usually has two cells. Vegetative cell forms pollen tube. Generative cell forms male gametes.
At shedding, most angiosperm pollen grains are two-celled. They contain a large vegetative cell and a smaller generative cell. The generative cell later divides to produce two male gametes.
- Option A) Components of embryo sac.
- Option B) Female reproductive structures.
- Option C) Not pollen cell types.
Used: NCERT Recall
- Option A โ Embryo sac.
- Option B โ Female structures.
- Option C โ Incorrect terms.
- Option D โ Correct.
- Final Answer โ Vegetative and Generative.
2 What will be the number of chromosomes in the gamete of maize if its meiocyte contains 20 chromosomes? (PYQ 2023 Shift 1)
Meiocyte is diploid (2n). Gametes are haploid (n). Meiosis reduces chromosome number by half.
Meiocytes undergo meiosis to produce gametes. During meiosis, the chromosome number is reduced from diploid (2n) to haploid (n). Since the meiocyte of maize contains 20 chromosomes (2n = 20), the resulting gametes will contain 10 chromosomes (n = 10).
- Option B) 20 โ Represents diploid chromosome number, not gametic number.
- Option C) 24 โ Not related to chromosome reduction from 20.
- Option D) 40 โ Chromosome number cannot double during gamete formation.
Used: Dimensional/Unit Analysis
- Option A โ Half of diploid number.
- Option B โ Original diploid count.
- Option C โ Arbitrary value.
- Option D โ Opposite of meiosis outcome.
- Final Answer โ Meiosis halves chromosome number.
3 Which layer of microsporangium nourishes the developing pollen grains? (PYQ 2023 Shift 1)
Innermost wall layer. Rich in nutrients. Feeds developing microspores.
Tapetum is the innermost layer of the microsporangium wall. It supplies nourishment and essential materials required for pollen grain development. It is metabolically active and often multinucleate.
- Option A) Epidermis โ Protective outer layer.
- Option B) Endothecium โ Helps anther dehiscence.
- Option C) Middle layer โ Temporary supporting layer.
Used: Elimination
- Option A โ Protection.
- Option B โ Dehiscence.
- Option C โ Support.
- Option D โ Nutrition.
- Final Answer โ Tapetum nourishes pollen grains.
4 Match the following: (PYQ 2023 Shift 1)
| List I | List II |
|---|---|
| A. Albuminous seed | I. Groundnut |
| B. Parthenocarpic fruit | II. Apple |
| C. Non-albuminous seed | III. Castor |
| D. False fruit | IV. Banana |
Castor โ Albuminous seed. Banana โ Parthenocarpic fruit. Groundnut โ Non-albuminous seed. Apple โ False fruit.
Albuminous seed retains endosperm (Castor). Non-albuminous seeds consume endosperm during development (Groundnut). Banana develops without fertilization and is parthenocarpic. Apple is a false fruit because the thalamus contributes to fruit formation.
- Option A โ Incorrect matching of albuminous and false fruit.
- Option C โ Multiple incorrect associations.
- Option D โ Albuminous and parthenocarpic fruit mismatched.
Used: Option Grouping
- Option A โ Partial mismatch.
- Option B โ All correct matches.
- Option C โ Multiple errors.
- Option D โ Multiple errors.
- Final Answer โ Only Option B satisfies all pairs.
5 Maximum number of male gametes produced from one pollen mother cell (microspore mother cell) will be : (PYQ 2023 Shift 2)
One PMC forms four microspores. Each pollen grain forms two male gametes. Total = 4 ร 2 = 8.
One pollen mother cell undergoes meiosis to produce four microspores. Each microspore develops into a pollen grain that ultimately produces two male gametes. Therefore, maximum male gametes = 4 ร 2 = 8.
- Option A) Too few.
- Option B) Counts only microspores.
- Option D) Exceeds biological limit.
Used: Substitution
- Option A โ Incorrect.
- Option B โ Microspore count only.
- Option C โ Correct calculation.
- Option D โ Excessive value.
- Final Answer โ Eight.
6
- Embryo develops after fertilization.
- The zygote gives rise to the embryo.
- In maize, the embryo forms the young plant.
The embryo of a seed develops from the zygote formed after fertilization. In maize grain, the embryonal axis and associated structures originate from the zygote.
Option A) Ovary cell โ Does not develop into the embryo.
Option C) Sepals โ Floral accessory structures.
Option D) Petals โ Floral accessory structures.
- Option A โ Not embryo origin.
- Option B โ Zygote develops into embryo.
- Option C โ Floral whorl.
- Option D โ Floral whorl.
Final Answer โ Zygote. โ Zygote โ Embryo.
7
- Maize is an endospermic seed.
- Endosperm stores food.
- It nourishes the developing embryo.
Maize is an endospermic seed. The endosperm persists in the mature seed and serves as the major food reserve supplying nutrients to the developing embryo.
Option A) Scutellum โ Cotyledon that absorbs nutrients from endosperm.
Option C) Coleorhiza โ Protective sheath covering the radicle.
Option D) Plumule โ Young shoot of the embryo.
- Option A โ Absorbs and transfers nutrients.
- Option B โ Food reserve and nourishment.
- Option C โ Protects radicle.
- Option D โ Young shoot.
- Final Answer โ Endosperm.
8
- Radicle covering = coleorhiza.
- It is a protective sheath.
- It is characteristic of monocot seeds.
In maize grain, the radicle is enclosed within a protective sheath called coleorhiza. This structure protects the radicle during seed germination.
Option A) Coleoptile โ Covers the plumule.
Option C) Scutellum โ Single cotyledon of maize.
Option D) Testa โ Seed coat.
- Option A โ Plumule sheath.
- Option B โ Radicle sheath.
- Option C โ Cotyledon.
- Option D โ Seed coat.
- Final Answer โ Coleorhiza.
9
- Scutellum is the cotyledon of maize.
- It lies between embryo and endosperm.
- It absorbs nutrients from the endosperm.
The scutellum is the single cotyledon present in monocot seeds such as maize. It absorbs nutrients from the endosperm and transfers them to the embryo.
Option A) Coleoptile โ Protective sheath covering the plumule.
Option B) Endosperm โ Food-storage tissue.
Option D) Coleorhiza โ Protective sheath covering the radicle.
- Option A โ Plumule sheath.
- Option B โ Nutritive tissue.
- Option C โ Monocot cotyledon.
- Option D โ Radicle sheath.
- Final Answer โ Scutellum.
10
- Plumule covering = coleoptile.
- It protects the young shoot.
- It is characteristic of monocot seeds.
In monocot seeds such as maize, the plumule is enclosed by a protective sheath called coleoptile. It protects the young shoot during germination.
Option A) Coleorhiza โ Surrounds the radicle.
Option B) Scutellum โ Single cotyledon of maize.
Option D) Testa โ Seed coat.
- Option A โ Radicle sheath.
- Option B โ Cotyledon.
- Option C โ Plumule sheath.
- Option D โ Seed coat.
- Final Answer โ Coleoptile.
11 In artificial hybridisation bagging is done to: (PYQ 2023 Shift 3)
Bagging follows emasculation. Protects stigma. Prevents unwanted pollen deposition.
In artificial hybridisation, the emasculated flower is covered with a bag to prevent contamination of the stigma by unwanted pollen grains. This ensures controlled pollination with desired pollen.
- Option A) Removal of anthers is emasculation.
- Option B) Not the purpose of bagging.
- Option C) Bagging prevents contamination, not pollination itself.
Used: NCERT Recall
- Option A โ Emasculation.
- Option B โ Incorrect.
- Option C โ Indirect effect.
- Option D โ Correct.
- Final Answer โ Option D.
12 Match List I with List II (PYQ 2023 Shift 3)
| List I | List II |
|---|---|
| A. Attaches ovule to the placenta | I. Hilum |
| B. Region where ovule fuses with its stalk | II. Chalaza |
| C. Place where integuments are not present | III. Funicle |
| D. Basal part of ovule | IV. Micropyle |
Funicle attaches ovule to placenta. Hilum is fusion point. Micropyle lacks integuments. Chalaza is basal region.
Funicle connects ovule to placenta. Hilum is the junction where ovule fuses with stalk. Micropyle is the opening left by integuments. Chalaza is the basal part opposite the micropyle.
- Option B) Hilum and micropyle mismatched.
- Option C) Chalaza incorrectly matched.
- Option D) Multiple mismatches.
Used: Option Grouping
- Option A โ Correct.
- Option B โ Incorrect.
- Option C โ Incorrect.
- Option D โ Incorrect.
- Final Answer โ Option A.
13 The method of embryo sac formation from a single megaspore is termed ______ development. (PYQ 2023 Shift 3)
One megaspore remains functional. Embryo sac develops from it. Most common type in angiosperms.
In most flowering plants, only one megaspore remains functional and develops into the embryo sac. Such development is called monosporic development.
- Option A) Embryo sac develops from four nuclei.
- Option C) Not a standard embryo sac type.
- Option D) Embryo sac develops from two nuclei.
Used: NCERT Recall
- Option A โ Tetrasporic.
- Option B โ Correct.
- Option C โ Incorrect.
- Option D โ Bisporic.
- Final Answer โ Monosporic.
14 Identify the correct statements with respect to female gametophyte. (PYQ 2023 Shift 3)
(A) Three cells at the chalazal end group together to form egg apparatus
(B) Female gametophyte is also known as embryo sac
(C) Six of the eight nuclei in the embryo sac are surrounded by cell walls and organised into cells
(D) Megaspore mother cell forms four megaspores by meiotic division
Choose the correct answer from the options given below:
Egg apparatus occurs at micropylar end. Female gametophyte = embryo sac. MMC undergoes meiosis.
Statement A is incorrect because the egg apparatus is present at the micropylar end. Statements B, C and D are correct according to the standard Polygonum type embryo sac development.
- Option A) Includes incorrect statement A.
- Option B) Includes incorrect statement A.
- Option D) Includes incorrect statement A.
Used: Elimination
- Option A โ A incorrect.
- Option B โ A incorrect.
- Option C โ Correct.
- Option D โ A incorrect.
- Final Answer โ Option C.
15 During megasporogenesis in a typical angiosperm ovule, which of the following correctly describes the formation and fate of megaspores? (PYQ 2023 Shift 3)
- The megaspore mother cell (MMC) is diploid.
- It undergoes meiosis and produces four haploid megaspores.
- Usually, three megaspores degenerate and only one remains functional.
- The functional megaspore later develops into the female gametophyte or embryo sac.
In most flowering plants, a single diploid megaspore mother cell differentiates within the nucellus of the ovule.
The MMC undergoes meiotic division and produces a tetrad of four haploid megaspores.
Usually, three of these megaspores degenerate, while only one functional megaspore continues its development.
The functional megaspore then undergoes mitotic divisions to form the mature embryo sac.
Therefore, Option A is correct.
Option B) Incorrect because the megaspore mother cell undergoes meiosis, not mitosis. The resulting megaspores are haploid, not diploid, and normally only one remains functional.
Option C) Incorrect because the nucellus does not undergo meiosis to form the embryo sac. A megaspore mother cell present within the nucellus undergoes meiosis.
Option D) Incorrect because the functional megaspore undergoes mitotic divisions, not meiotic divisions, during embryo-sac development.
- Identify the starting cell โ Megaspore mother cell (MMC).
- Recall its ploidy โ Diploid (2n).
- Recall the type of division โ Meiosis.
- Result โ Four haploid megaspores.
- Normal fate โ Three degenerate and one remains functional.
- Final Answer โ Option A.
16 Which part of the ovule differentiates a large cell with dense cytoplasm and a prominent nucleus during megasporogenesis? (PYQ 2023 Shift 3)
Archesporial cell develops here. Gives rise to MMC. Initiates megasporogenesis.
A hypodermal cell in the micropylar region of the nucellus enlarges, develops dense cytoplasm and a prominent nucleus, and differentiates into the archesporial cell, which ultimately forms the megaspore mother cell.
- Option B) Not the site of archesporial differentiation.
- Option C) Not specified in NCERT.
- Option D) Does not form MMC.
Used: NCERT Recall
- Option A โ Correct.
- Option B โ Incorrect.
- Option C โ Incorrect.
- Option D โ Incorrect.
- Final Answer โ Option A.
17 How many mitotic divisions occur in the nucleus of the functional megaspore to form embryo sac? (PYQ 2023 Shift 3)
Functional megaspore is haploid. Undergoes three mitotic divisions. Produces eight nuclei.
The functional megaspore undergoes three successive mitotic divisions: 1 โ 2 nuclei 2 โ 4 nuclei 4 โ 8 nuclei This results in the typical eight-nucleate embryo sac.
- Option A) Produces only four nuclei.
- Option B) Excessive divisions.
- Option C) Produces sixteen nuclei.
Used: Substitution
- Option A โ Too few.
- Option B โ Too many.
- Option C โ Produces 16 nuclei.
- Option D โ Produces 8 nuclei.
- Final Answer โ Three.
18 In a velvet grass seed, the cotyledon is called : (PYQ 2024 Shift 1, 2024 Shift 2)
Grass seeds are monocot seeds. Monocot cotyledon is called scutellum. Helps absorb nutrients from endosperm.
In monocotyledonous seeds such as grasses, the single cotyledon is called the scutellum. It lies between the embryo and endosperm and absorbs nutrients from the endosperm during germination for transfer to the growing embryo.
- Option B โ Coleorrhiza is the protective sheath covering the radicle.
- Option C โ Coleoptile is the protective sheath covering the plumule.
- Option D โ Testa is the seed coat.
Used: Odd One Out
- Option A โ Cotyledon structure.
- Option B โ Radicle covering.
- Option C โ Plumule covering.
- Option D โ Seed coat.
- Final Answer โ Only scutellum is the cotyledon.
19 Which one of the following is not associated with megasporangium ? (PYQ 2024 Shift 1)
Megasporangium refers to ovule. Funicle, integument and micropyle are ovule parts. Generative cell belongs to pollen grain.
The megasporangium (ovule) consists of nucellus, integuments, micropyle and funicle. The generative cell is a component of the male gametophyte (pollen grain) and is not associated with the ovule.
- Option A โ Funicle attaches ovule to placenta.
- Option B โ Integuments surround the nucellus.
- Option D โ Micropyle is the opening in ovule.
Used: Odd One Out
- Option A โ Ovule structure.
- Option B โ Ovule structure.
- Option C โ Male gametophyte structure.
- Option D โ Ovule structure.
- Final Answer โ Generative cell.
20 In diploid organisms, which of the following undergoes meiosis? (PYQ 2024 Shift 1)
Meiosis forms haploid spores. Sporogenous tissue is diploid. Pollen grains and synergids are already haploid.
The diploid sporogenous tissue inside microsporangia undergoes meiosis to produce haploid microspores. These later develop into pollen grains.
- Option A โ Does not undergo meiosis.
- Option C โ Product of meiosis.
- Option D โ Haploid female gametophyte cell.
Used: Elimination
- Option A โ No meiosis.
- Option B โ Undergoes meiosis.
- Option C โ Produced after meiosis.
- Option D โ Haploid cell.
- Final Answer โ Sporogenous tissue.
21 Which one of the following guides the entry of the pollen tube into the embryo sac? (PYQ 2025 Shift 1)
Present in synergid cells. Guides pollen tube towards egg apparatus. Helps in pollen tube reception.
The filiform apparatus is a specialized structure present at the micropylar end of synergid cells. It plays a crucial role in attracting and guiding the pollen tube into the embryo sac. After reaching the embryo sac, the pollen tube enters one synergid through the filiform apparatus and releases the male gametes. Thus, the filiform apparatus acts as the guiding structure during fertilization in angiosperms.
- A) Antipodal cells
- Located at the chalazal end and mainly provide nourishment. They do not guide the pollen tube.
- C) Micropyle
- It is the opening through which the pollen tube enters the ovule, but it does not actively guide it.
- D) Synergids
- Synergids help in pollen tube reception, but the specific guiding structure within them is the filiform apparatus.
Used: Elimination
- Option A โ Located at opposite end of embryo sac.
- Option B โ Known guiding structure.
- Option C โ Only an opening.
- Final Answer โ Based on elimination.
"Filiform = File the pollen tube in the right direction."
22 Which one of the following is opposite part of micropylar end of ovule? (PYQ 2025 Shift 1)
Micropyle at one end. Chalaza at opposite end. Characteristic ovule structure.
The chalaza is the basal region of the ovule opposite to the micropylar end. It is the area where integuments and nucellus merge. The embryo sac is situated between the micropylar and chalazal ends.
- A) Hilum
- Attachment point of ovule.
- C) Funicle
- Stalk connecting ovule and placenta.
- D) Nucellus
- Nutritive tissue of ovule.
Used: NCERT Recall
- Option A โ Attachment region.
- Option B โ Opposite of micropyle.
- Option C โ Connecting stalk.
- Final Answer โ Based on NCERT recall.
Micro โ Chalaza (Opposite Ends)
23
Seed develops from ovule. Endosperm provides nourishment. Endosperm does not become the seed.
After fertilization, the ovule develops into a seed while the ovary develops into a fruit. Endosperm is a nutritive tissue formed from the primary endosperm nucleus and supplies nutrients to the developing embryo. Therefore, the statement that endosperm develops into seed is incorrect.
- B) Ovary develops into fruit
- Correct statement.
- C) Fusion of polar nuclei
- Occurs during triple fusion.
- D) Syngamy is fusion of male and female gamete
- Correct definition of syngamy.
Used: Elimination
- Option A โ Incorrect developmental pathway.
- Option B โ Correct post-fertilization event.
- Option C โ Correct reproductive process.
- Final Answer โ Based on elimination.
Ovule โ Seed, Ovary โ Fruit
24
Dicot embryo passes through globular stage. Heart-shaped stage follows. Bird is not an embryonic stage.
Development of a dicot embryo proceeds through stages such as proembryo (pre-embryo), globular embryo, heart-shaped embryo, and mature embryo. "Bird" is not a recognized developmental stage in plant embryology. Hence it is the incorrect option.
- A) Heart-shaped
- A valid dicot embryo stage.
- B) Globular
- An early embryonic stage.
- C) Pre-embryo
- Occurs before later embryo differentiation.
Used: Odd One Out
- Option A โ Embryonic stage.
- Option B โ Embryonic stage.
- Option C โ Embryonic stage.
- Final Answer โ Based on odd one out.
Globular โ Heart-shaped โ Mature
25
Coconut water is liquid endosperm. Rich in nutrients. Formed by free nuclear divisions.
In coconut, the liquid found inside tender fruits is free nuclear endosperm. During development, nuclei divide repeatedly without immediate cell wall formation, creating a multinucleate liquid tissue. This liquid later contributes to the nutritive endosperm of the seed.
- B) Synergids
- Cells associated with the egg apparatus.
- C) Antipodal cells
- Located at the chalazal end of embryo sac.
- D) Scutellum
- Cotyledon of monocot embryo.
Used: NCERT Recall
- Option A โ Standard NCERT example.
- Option B โ Embryo sac cell.
- Option C โ Embryo sac cell.
- Final Answer โ Based on NCERT recall.
Tender Coconut Water = Liquid Endosperm
26
Male and female gametes fuse. Diploid zygote is formed. Fundamental fertilization event.
Syngamy is the fusion of one male gamete with the egg cell. This fusion restores the diploid chromosome number and forms the zygote. Triple fusion forms the primary endosperm nucleus and does not produce the zygote.
- A) Emasculation
- Removal of anthers during artificial hybridization.
- B) Triple fusion
- Forms primary endosperm nucleus.
- D) Bagging
- Prevents unwanted pollination.
Used: NCERT Recall
- Option A โ Hybridization technique.
- Option B โ Endosperm formation.
- Option C โ Zygote formation.
- Final Answer โ Based on fertilization process.
Syngamy = Sperm + Egg
27
Zygote is diploid (2n). Egg cell is haploid (n). Haploid number is half of diploid number.
A zygote is formed by the fusion of two haploid gametes and therefore contains the diploid chromosome number (2n). If the zygote contains 38 chromosomes, the haploid number is 19. Thus, the egg cell contributing to the zygote would contain 19 chromosomes.
- A) 38
- Represents diploid number, not haploid.
- B) 57
- Not related to chromosome reduction.
- D) 76
- Represents chromosome doubling beyond diploid level.
Used: Substitution
- Option A โ Diploid count.
- Option B โ Incorrect calculation.
- Option C โ 38 รท 2 = 19.
- Final Answer โ Based on chromosome number reduction.
Gamete = Half of Zygote
